Question

potassium crystallizes in BCC lattice. Calculate approx no of unit cells in 2 g of potassium. Atomic mass of potassium = 39 u

Answer 1

Dear Student,

1 mol of potassium = 39g=6.02 x 10²³ atoms

number of atoms present in 1 g of potassium =6.02 x 10²³ /39

number of atoms present in 2g of potassium =6.02 x 10²³ x 2 /39

= 0.308 x 10²³

Number of atoms in bcc = 2

Number of unit cell present = 0.308 x 10²³/2

= 0.154 x 10²³

= 1.54 x 10²²