Focal length of A is, F = 0.15 m
Suppose focal length of B is F'.
Now,the power of the combination of lenses=5D
P = 1/F + 1/F'
=> 5 = 1/0.15 + 1/F'
=> F' = -0.6 m ( it is a concave lens)
Thus, lens B is a concave lens of focal length 60 cm and power -1.67 D.