Prove that if n is a positive even integer, then 24 divides n(n+1)(n+2).
Given: n is a positive even integer
Now we know that one out of three consecutive integer is divisible by 3
⇒ 3 is a factor of n(n+1)(n+2)
also since n is even
∴ one out of n and (n+2) will have a factor 2 and the other will have a factor 4
Thus 2 × 4 = 8 is a factor of n(n+2) or n(n+1)(n+2)
Hence, 3 × 8 = 24 is a factor of n(n+1)(n+2)