Question

prove that sec 30 degrees tan 60 degrees + sin 45 degrees cosec 45 degrees +cos 30 degrees cot 60 degrees =7/2

Answer 1

$$\begin{gathered} \mathrm{LHS}=\sec 30°\tan 60°+\sin 45°\mathrm{cosec}45°+\cos 30°\cot 60° \\ =\frac{2}{\sqrt{3}}\times \sqrt{3}+\frac{1}{\sqrt{2}}\times \sqrt{2}+\frac{\sqrt{3}}{2}\times \frac{1}{\sqrt{3}} \\ =2+1+\frac{1}{2} \\ =\frac{4+2+1}{2} \\ =\frac{7}{2} \\ =\mathrm{RHS} \end{gathered}$$