Prove this identity-rnIf sin A - sin2 A - 1- prove that cos2 A - cos4 A - 1-

Now from the first equation , sinA + sin2A = 1 sinA = 1 sin2A nbsp; Using the identity( sin2A nbsp;= 1 nbsp;cos2A) we get , sinA = cos2A ...

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Derivative of Some Standard Functions

Prove this id...

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Prove this identity.
rn
If sin A + sin² A = 1, prove that cos² A + cos⁴ A = 1.

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{cos}^{4} A - {cos}^{2} A = {sin}^{4} A - {sin}^{2} A

sin θ + {sin}^{2} θ = 1

{cos}^{2} θ + {cos}^{4} θ = 1

4 [{sin}^{4} 30^{\circ} + {cos}^{4} 60^{\circ}] - 3 [{cos}^{2} 45^{\circ} - {sin}^{2} 90^{\circ}] = 2

\frac{1 - c o s 2 θ + s i n 2 θ}{1 + c o s 2 θ + s i n 2 θ} = t a n θ

\frac{{cos}^{4} x}{{cos}^{2} y} + \frac{{sin}^{4} x}{{sin}^{2} y} = 1

\frac{{cos}^{4} y}{{cos}^{2} x} + \frac{{sin}^{4} y}{{sin}^{2} x} = 1

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