Q.5 A man weighs 130.4 N on the moon. If the acceleration due to gravity on the moon is 1.63 m/s2. Find the mass of the man and his weight on the earth( g = 9.8 m/s2)

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Solution

$W e k n o w t h a t, W e i g h t = M a s s \times A c c e l e r a t i o n d u e t o g r a v i t y t h e r e f o r e, M a s s o f t h e m a n = \frac{130.4}{1.63} = 80 k g n o w, w e i g h t o f t h e m a n o n e a r t h = M a s s \times a c c e l e r a t i o n d u e t o g r a v i t y o n e a r t h = 80 \times 9.81 = 784.8 N$

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Q.5 A man weighs 130.4 N on the moon. If the acceleration due to gravity on the moon is 1.63 m/s2. Find the mass of the man and his weight on the earth( g = 9.8 m/s2)

We know that, Weight = Mass × Acceleration due to gravitytherefore,Mass of the man = 130.41.63= 80 kgnow, weight of the man on earth = Mass × acceleration due to gravity on earth = 80 × 9.81 = 784.8 N