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Question

Q : A car moves2/5th of distance with v1 velocity and left of 3/5th distance with v2 velocity find its average speed?

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Solution

Let the total distance covered by the car = x
Time taken by the car to cover 2/5 of total distance x with velocity v1 is given by :
t1 =25 xv1 = 2 x 5 v1

Time taken by the car to cover remaining 3/5 of total distance x with velocity v2 is given by :
t2 = 35 xv2 = 3 x5 v2
Average Speed of the car = Total distance travelledTotal Time taken = xt1 + t2 = x2 x5 v1 + 3 x5 v2

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