Question

$P,Q$ and $R$ are three coplanar forces acting at a point and are in equilibrium. Given $P=1.9381kgwt.,\sin {\theta }_1=0.9659,$ the value of $R$ is (in $kgwt.)$

Answer 1

Given, $P=1.9318kgwt$

$\sin {\theta }_1=0.9659$

Using Lami's theorem,

$\frac{P}{\sin {\theta }_1}=\frac{Q}{\sin {\theta }_2}=\frac{R}{\sin {150}^0}$

$\frac{1.9318}{0.9659}=\frac{R}{\sin {150}^0}$

$R=\frac{1.9318\times 0.5}{0.9659}=1kgwt$

Final answer: 1