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Question

P & Q are the points of contact of the tangents drawn from the point T to the parabola y2=4ax. If PQ be the normal to the parabola at P, then show that TP is bisected by the directrix.

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Solution

Let P(at21,2at1)&Q(at22,2at2) on y2=4ax
co-ordinate of T(at1t2,a(t1+t2)) which is point of intersection of tangent at P & Q equation of PQ which is normal at P
y+t1x=2at1+at31...(1)
equatioin of PQ is
(t1+t2)y=2x+2at1t2...(2)
equation (1) & (2) are same
Compare slope 2t1+t2=t1
t21+t1t2=2
Now mid point of TP
x=at21+at1t22=a(t21+t1t2)2
x=a(2)2=a
x=a which is directrix
Hence TP bisect the directrix.

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