Let P(at21,2at1)&Q(at22,2at2) on y2=4ax
co-ordinate of T(at1t2,a(t1+t2)) which is point of intersection of tangent at P & Q equation of PQ which is normal at P
y+t1x=2at1+at31...(1)
equatioin of PQ is
(t1+t2)y=2x+2at1t2...(2)
equation (1) & (2) are same
Compare slope 2t1+t2=−t1
⇒t21+t1t2=−2
Now mid point of TP
x=at21+at1t22=a(t21+t1t2)2
x=a(−2)2=−a
x=−a which is directrix
Hence TP bisect the directrix.