Question 9
Two congruent circles intersect each other at points A and B. Through A any line segment PAQ is drawn so that P, Q lie on the two circles. Prove that BP = BQ.

Q. A variable line

L

passing through the point

B (2, 5)

intersects the lines

2 x^{2} - 5 x y + 2 y^{2} = 0

P

and

Q

. Find the locus of the point

R

L

such that distance

B P, B R

and

B Q

are in harmonic progression.

Join BYJU'S Learning Program

P & Q are two points at the same distance and in the same horizontal plane form a current carrying vertical conductor. The point P is located towards the west and the point Q is towards the east. The current is vertically downwards. If BP & BQ be the net magnetic fields at P & Q then :

The correct option is A BP=BQFor in-finely long current carrying conductor; ⇒B=μoI4πa =Bα1a∵ distance from conductor of both points are same. so, magnetic field at both points are equal.⇒BP=BQ.

P & Q are two points at the same distance and in the same horizontal plane form a current carrying vertical conductor. The point P is located towards the west and the point Q is towards the east. The current is vertically downwards. If $B_{P}$ & $B_{Q}$ be the net magnetic fields at P & Q then :

The correct option is A $B_{P} = B_{Q}$
For in-finely long current carrying conductor;
$\Rightarrow B = \frac{μ_{o} I}{4 π a}$
$= B α \frac{1}{a}$
$∵$ distance from conductor of both points are same. so, magnetic field at both points are equal.
$\Rightarrow B_{P} = B_{Q} .$