P- Q have position vectors a- b- relative to the origin - O- and X- Y divide P-Q- intermally and extemally respectively in the ratio 2-1- then vector X-Y-

The correct option is D 43(b⃗ a⃗) X divides nbsp; P⃗Q⃗ nbsp;internally in 2:1 . Thus, nbsp; X⃗ = a⃗ + 2b⃗2 + 1 Y divides ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Section Formula

P, Q have pos...

Question

$P, Q$ have position vectors $\to a$ & $\to b$ relative to the origin ' $O$ ' and $X, Y$ divide $\to P Q$ intermally and extemally respectively in the ratio $2 : 1$ , then vector $\to X Y =$

\frac{3}{2} (\to b - \to a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{3} (\to c - \to a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{6} (\to b - \to a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{3} (\to b - \to a)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

2 \to a + 3 \to b - \to c, \to a - 2 \to b + 3 \to c, 3 \to a + 4 \to b - 2 \to c a n d \to a - 6 \to b + 6 \to c

\to a, \to b a n d \to c

A, B, C, D

\to a, \to b, 2 \to a + 3 \to b

\to a - 2 \to b

- - \to D B = 3 \to b - \to a

- - \to A C = \to a + 3 \to b

\to A, \to B, \to C

\to a, \to b, \to c

P

\to A B

3 : 4

Q

\to B C

2 : 1

\to P Q

\to a, \to b, \to c

\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}

\to q = \frac{\to c \times \to a}{[\to a \to b \to c]}

\to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(2 \to a + 3 \to b + 4 \to c) . \to p + (2 \to b + 3 \to c + 4 \to a) . \to q +

(2 \to c + 3 \to a + 4 \to b) . \to r =

\to a, \to b

- - \to A B

- - \to X Y

Join BYJU'S Learning Program