wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

P,Q,R and S are four points with the position vectors, 3i4j+5k,4k,4i+5j+k and 3i+4j+3k respectively. Then the line PQ meets the line RS at the point


A

3i+4j+3k

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

3i+4j+3k

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

i+4j+k

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

i+j+k

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

3i+4j+3k


Equation of PQ:x3=y4=z41a point A on PQ=(3λ,4λ,λ+4)Equation of RSx+41=y51=z12=ma point on RS, B=(m4,m+5,2m+1)to intersect A = Bλ=1,m=1Point is (3,4,3)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Projection of a Line Segment on a Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon