Question

	P	Q	R	M	T
$T_{2}S{O}_4$	$\times$	$\times$	$\times$	$\times$	$\times$
$QS{O}_4$	$\times$	$\times$	$\times$	$\times$	$✓$
$P_{2}S{O}_4$	$\times$	$✓$	$\times$	$\times$	$✓$
$MS{O}_4$	$✓$	$✓$	$\times$	$\times$	$✓$
$RS{O}_4$	$✓$	$✓$	$\times$	$✓$	$✓$

$\times -Noreaction$

$✓-Displacementreaction$

Different metals P, Q, R, M and T are dipped in different salt solutions one by one and the observations are recorded in the form of given table. Observe the table carefully.

Q is the metal that is more reactive than P but less reactive than T.

• A. True
• B. False

Answer 1

The correct option is A True

As we know, higher reactive metal will replace lower reactive metal from its solution and from the figure, it can be seen that Q can replace P but not able to replace T. So Q is more reactive than P but less reactive than T.

The order of reactivity for the given metals is-
$T>Q>P>M>R$