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Question

P,Q,R,S,T are points on a circle with centre O so that PTQ= 2 x RTS and PQ is parallel to RS. If P,O,Q are in a straight line, then the value of SOQ is ___.

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Solution

PTQ= 90 (angle in a semi circle)

Hence RTS = 45.

ROS = 90 ( Inscribed angle= 2 ×Angle at circumference)

OR=OS=OR (radius)

RSO = SOQ= 45 (interior alternate angles)


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