Q. the near point of a hypermetropic eye is at 75 cm from the eye.what is the power of the lens required to enable him to read clearly a book held at 25 cm from the eye.

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Solution

Given:
u = - 25 cm , v = -75 cm
Lens formula: 1/v - 1/u =1 /f
-1/75 + 1/25 = 1/f
f = 75/2 cm
P = 1/f = + 2/75 D

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Q. the near point of a hypermetropic eye is at 75 cm from the eye.what is the power of the lens required to enable him to read clearly a book held at 25 cm from the eye.

Given:u = - 25 cm , v = -75 cmLens formula: 1/v - 1/u =1 /f-1/75 + 1/25 = 1/ff = 75/2 cm P = 1/f = + 2/75 D

Given:
u = - 25 cm , v = -75 cm
Lens formula: 1/v - 1/u =1 /f
-1/75 + 1/25 = 1/f
f = 75/2 cm
P = 1/f = + 2/75 D