Question

Q1) A natural number when increased by 12 equal 160 times its reciprocals. find the number.

Q2) The difference of two numbers is 4. If the difference of their reciprocals is 4/21, find the numbers.

Answer 1

A natural number when increased by 12 equal 160 times its reciprocals. find the number.

Let the number be 'x'.

x+12 = 160 * 1/x

x+12 = 160/x

x^2+12x = 160

x^2+12x-160=0

(x-8)(x+20)=0

x=8 (x=-20 is invalid because x is natural number)