Question

relation between escape velocity and orbital velocity

Answer 1

The orbital velocity of an earth's satellite $v_0=\sqrt{\left(g{R}_0\right)}$
and escape velocity of a body projected from the earth is $$\begin{gathered} v_e=\sqrt{\left(2g{R}_e\right)} \\ \cdots \frac{v_e}{v_0}=\sqrt{2} \\ or{v}_e=\sqrt{2}{v}_o \end{gathered}$$