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Conductance and Conductivity

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Question

Resistance of a conductivity cell filled with 0.1 M is 100 ohm. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of the 0.02 M KCl solution. Conductivity of 0.1 M KCl solution is 1.29*10^-2 S cm^-1.

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Solution

Cell constant can be calculated using 0.1 M KCl
= Îº Ã— R
= 0.0129 * 100
= 1.29 cm^-1
Calculating conductivity of 0.02 M KCl solution
Îº = Cell constant / Resistance
= 1.29 / 520
= 2.48 * 10^-3 S cm^-1
Therefore, molar conductivity:
Î›m = 10³ Îº / M
= 10³ * 2.48 * 10^-3/0.02
= 124 S cm² mol^-1

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