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Question

Solve the following system of inequations

x2 + x + 8 less than 0

x2 + 6x + 5 greater than 0

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Solution

1)x2+x +8 < 0 Here D <0So x =-1±1-322 =-1±i322Hence the interval is -1-i322<x<-1+i322 2) x2 +6x + 5 >0 (x+1)(x+5) >0x <-5 and x >-1

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