wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following system of inequations

x2 + x + 8 less than 0

x2 + 6x + 5 greater than 0

Open in App
Solution

1)x2+x +8 < 0 Here D <0So x =-1±1-322 =-1±i322Hence the interval is -1-i322<x<-1+i322 2) x2 +6x + 5 >0 (x+1)(x+5) >0x <-5 and x >-1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Addition and Subtraction of Integers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon