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Question

1. A circular cycle track has a circumference of 314 m with AB as one of its diameter. A cyclist travels from A to B along the circular path with a velocity of constant magnitude 5.7 m/s. Calculate

a) The distance moved by the cyclist b) the displacement of the cyclist if AB represents north-south direction c) the average velocity of the cyclist

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Solution

Let, ‘r’ be the radius of the circular track.

Given,

Circumference, 2πr = 314

=> 2(3.14)r = 314

=> r = 50 m

Therefore, Diameter AB = 2r = 100 m

Speed along the circular path from A to B is 5.7 m/s.

a)

Distance moved by the cyclist is half the circumference, which is 314/2 = 157 m

b)

If AB represents North-South direction then displacement is from A to B which is AB = 100 m and the direction is from north to south.

c)

Time taken to cover half circle is, t = 157/5.7 = 27.54 s

While, the displacement is only, AB = 100 m

So, average velocity is, v = AB/t = 3.6 m/s


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