A cricketer canthrow a ball to a maximum horizontaldistance of 100 m. How much high above the ground can the cricketerthrow the same ball?
Maximumhorizontal distance,R =100 m
Thecricketerwill only be able to throw the ball to the maximum horizontaldistance when the angle of projection is 45°,i.e., θ= 45°.
Thehorizontalrange for a projection velocity v,is given by the relation:
Theball willachieve the maximum height when it is thrown vertically upward. Forsuch motion, the final velocity vis zero at the maximum height H.
Acceleration,a= –g
Usingthethird equation of motion: