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Question

A cricketer canthrow a ball to a maximum horizontaldistance of 100 m. How much high above the ground can the cricketerthrow the same ball?

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Solution

Maximumhorizontal distance,R =100 m

Thecricketerwill only be able to throw the ball to the maximum horizontaldistance when the angle of projection is 45°,i.e., θ= 45°.

Thehorizontalrange for a projection velocity v,is given by the relation:

Theball willachieve the maximum height when it is thrown vertically upward. Forsuch motion, the final velocity vis zero at the maximum height H.

Acceleration,a= –g

Usingthethird equation of motion:


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