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Question
Amagnetic needle free to rotate in a vertical plane parallel to themagnetic meridian has its north tip pointing down at 22º withthe horizontal. The horizontal component of the earth’smagnetic field at the place is known to be 0.35 G. Determine themagnitude of the earth’s magnetic field at the place.
Amagnetic needle free to rotate in a vertical plane parallel to themagnetic meridian has its north tip pointing down at 22º withthe horizontal. The horizontal component of the earth’smagnetic field at the place is known to be 0.35 G. Determine themagnitude of the earth’s magnetic field at the place.
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Solution
Horizontalcomponent of earth’s magnetic field, BH= 0.35 G
Anglemade by the needle with the horizontal plane = Angle of dip = 
Earth’smagnetic field strength = B
Wecan relate Band BHas:
Hence,the strength of earth’s magnetic field at the given location is0.377 G.
Horizontalcomponent of earth’s magnetic field, BH= 0.35 G
Anglemade by the needle with the horizontal plane = Angle of dip =
Earth’smagnetic field strength = B
Wecan relate Band BHas:
Hence,the strength of earth’s magnetic field at the given location is0.377 G.
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