) At 25ºC and 760mm oh Hg pressure a gas occupies 600 ml volume.What will be
its pressure at a height where temperature is 10ºC and volume of gas is 640ml.

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Solution

Using ideal gas equation, PV=nRT,
where n and R are constant for this case.
So, P₁ V₁ /T₁ = P₂ V₂ / T₂
P₁ = 760 mm Hg
P₂ =x
V₁=600 ml
V₂= 640 ml
T₁ =298 K
T₂= 283 K
putting above values in the above equation, we get p₂ = 676.64 mm of Hg

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) At 25ºC and 760mm oh Hg pressure a gas occupies 600 ml volume.What will beits pressure at a height where temperature is 10ºC and volume of gas is 640ml.

Using ideal gas equation, PV=nRT, where n and R are constant for this case.So, P1 V1 /T1 = P2 V2 / T2P1 = 760 mm HgP2 =xV1=600 mlV2= 640 mlT1 =298 KT2= 283 Kputting above values in the above equation, we get p2 = 676.64 mm of Hg

) At 25ºC and 760mm oh Hg pressure a gas occupies 600 ml volume.What will be
its pressure at a height where temperature is 10ºC and volume of gas is 640ml.

Using ideal gas equation, PV=nRT,
where n and R are constant for this case.
So, P₁ V₁ /T₁ = P₂ V₂ / T₂
P₁ = 760 mm Hg
P₂ =x
V₁=600 ml
V₂= 640 ml
T₁ =298 K
T₂= 283 K
putting above values in the above equation, we get p₂ = 676.64 mm of Hg