Question

Calculate the force between 2 alpha particles seperated by a distance of 3.2 x 10^-11m .

Answer 1

According to Coulomb’s law of electrostatic force:

F= Kq₁q₂/r²

Here q₁ = q₂ = 2 x(1.6 x 10^-19)C = 3.2 x 10^-19C

r= 3.2 x 10 ^-11 m

$K=9\times {10}^{9}N{m}^2/C^2$

Therefore,

$F=9\times {10}^9\times \frac{(3.2\times {10}^{-19}{)}^2}{(3.2\times {10}^{-11}{)}^2}=9\times {10}^9\times \frac{(10.24\times {10}^{-38})}{(10.24\times {10}^{-22})}=9\times {10}^{-7}$ N.