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Question

Similarly, second and third periods can accommodate 8 and 18 electrons respectively. Since their outermost shells can contain only 8 electrons, there are only 8 elements in both the periods. -pllz explain this again.

i shall be thankful.

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Solution

Using the formula...

2n2.

For second period...

n=2

Hence the maximum possible number of electrons in 2nd period = 2 x (2)2 =2 x4 = 8.

For 3rd period..

n=3

Hence the maximum possible number of electrons in 3rd period = 2 x (3)2 = 18


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