State the type of reactions taking place in the below equations and also balance these equations.
(i) K + H₂O - KOH + H₂
(ii) CuSO₄ + NaOH - Cu(OH)₂ + Na₂SO₄

Open in App

Solution

(i) Single displacement reaction. K displaces H₂ from water.
Balanced equation : 2K + 2H₂O ----> 2KOH + H₂
(ii) Double displacement reaction. Components of the two reacting molecules are exchanged.
Balanced equation : CuSO₄ + 2NaOH -----> Cu(OH)₂ + Na₂SO₄

Suggest Corrections

Similar questions

C u S O_{4} + N a O H ⟶ C u (O H)_{2} + N a_{2} S O_{4}

C H_{4} + 2 O_{2} \to 2 H_{2} O

P b (N O_{3})_{2} + 2 K I \to P b I_{2} + 2 K N O_{2}

C a O + H_{2} O \to C a (O H)_{2}

N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O

What type of reactions are represented by the following equations

(a) $C a O + C O_{2} ⟶ C a C O_{3}$

(b) $2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}$

(d) $N H_{4} N O_{2} ⟶ N_{2} + 2 H_{2} O$

(e) $C u S O_{4} + 2 N a O H ⟶ C u (O H)_{2} + N a_{2} S O_{4}$

NaOH + H_{2} {SO}_{4} \to {Na}_{2} {SO}_{4} + H_{2} O

Join BYJU'S Learning Program