(1) Calculate the number of molecules of water present in 1L of water . density of water is 1gm ml^-1 [Atomic mass of O=16.0u, H=1.0 u ]

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Solution

1 L of water = 1000ml of water = 1000 gms of water (density = 1g/cc)
Mol wt of water i.e. H₂O = (2x1)+16 = 18
No. of moles of water = 1000/18 = 55.55 moles
No. of molecules = 55.55 moles x (6.023 x 10²³) -------(avogadro's no.)
= 334.57 x 10²³ molecules of water.

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