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Question

Briefly describe the Rutherford’s scattering experiment about the discovery of nucleus.

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Solution

Rutherford designed an experiment for this. In this experiment, fast moving alpha (α)-particles were made to fall on a thin gold foil. He selected a gold foil because he wanted as thin a layer as possible. This gold foil was about 1000 atoms thick. α-particles are doubly-charged helium ions. Since they have a mass of 4 u, the fast-moving α-particles have a considerable amount of energy.

It was expected that α-particles would be deflected by the sub-atomic particles in the gold atoms. Since the α-particles were much heavier than the protons ,he did not expect to see large deflections. But, the α-particle scattering experiment gave totally unexpected results:

i)Most of the fast moving α-particles passed straight through the gold foil.

(ii)Some of the α-particles were deflected by the foil by small angles.

(iii)Surprisingly one out of every 12000 alpha particles appeared to rebound.

Rutherford concluded from the α-particle scattering experiment that :

(i)Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected.
(ii)Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.
(iii)A very small fraction of α-particles were deflected by very large angles, indicating that all the positive charge and mass of the gold atom were concentrated in a very small volume within the atom.


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