Question

Two persons pull a rope towards themselves. Each person exets a force of 100N on the rope. Find Y, if change in length is 1cm . Original length = 1m and area of cross section = 2cm²

Answer 1

$$\begin{gathered} Y=\frac{Fl}{A∆l} \\ F=2\times 100=200N \\ l=1m \\ ∆l=0.01m \\ A=2\times {10}^{-4}{m}^2 \\ SoY=\frac{200\times 1}{2\times {10}^{-4}\times 0.01} \\ Y={10}^{8}N{m}^{-2} \end{gathered}$$