Solve this-An inductor -i- capacity -c- and resistor -r- are connected to an AC source of angular frequency -w- - in 3 different combinations - RC- CL- RL- Assume WL - 1-WC- If proved drawn by the 3 are - P1- P2- nbsp-P3 then -a- P1 gt- P3 gt- P2 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -b- P1 - P3 gt- P2-c- P1 - P2 - P3 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -d- P1 - P3 lt- P2-

Dear Student, The LC circuit draws no power. But when, nbsp; #969;L=1 #969;C, Then the impedances of the RC and RL nbsp;circuits are equal, and thus t ...

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Byju's Answer

Standard X

Physics

Alternating Current and Direct Current

Solve this: ...

Question

Solve this:
An inductor (i), capacity (c) and resistor (r) are connected to an AC source of angular frequency 'w' ; in 3 different combinations : RC, CL, RL. Assume WL = 1/WC. If proved drawn by the 3 are : P₁, P₂, P₃ then :
(a) P₁ > P₃ > P₂ (b) P₁ = P₃ > P₂
(c) P₁ = P₂ = P₃ (d) P₁ = P₃ < P₂

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Solution

Dear Student,

The LC circuit draws no power. But when,
$ω L = \frac{1}{ω C}$ , Then the impedances of the RC and RL circuits are equal, and thus they draw the same power.
So the right option in (b).

Regards

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Solve this: An inductor (i), capacity (c) and resistor (r) are connected to an AC source of angular frequency 'w' ; in 3 different combinations : RC, CL, RL. Assume WL = 1/WC. If proved drawn by the 3 are : P1, P2, P3 then : (a) P1 > P3 > P2 (b) P1 = P3 > P2 (c) P1 = P2 = P3 (d) P1 = P3 < P2

Dear Student, The LC circuit draws no power. But when, ωL=1ωC, Then the impedances of the RC and RL circuits are equal, and thus they draw the same power. So the right option in (b). Regards

Dear Student,

The LC circuit draws no power. But when,
$ω L = \frac{1}{ω C}$ , Then the impedances of the RC and RL circuits are equal, and thus they draw the same power.
So the right option in (b).

Regards