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Standard XII

Chemistry

Longest Chain Rule

Suppose we em...

Question

Suppose we employ a system in which the unit of mass equals 100 kg , the unit of length equals 1 km and the unit of time equals 100s
and call the energy eluoj (joule in reverse order) , then 1 elouj= how many joules

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Solution

1 joule = 1 kgm²s^-2
Suppose mass = 100 kg, length = 1 km, time = 100 s
Let say 1 joule = n₁ * new unit(1 elouj)
n₁= 1 [kg/100 kg] [m²/10⁶ m²][s/100s]^-2
= 10^-210^-610^-4=10^-12joule
1 elouj = 10^-12joule

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Suppose we employ a system in which the unit of mass equals 100 kg , the unit of length equals 1 km and the unit of time equals 100sand call the energy eluoj (joule in reverse order) , then 1 elouj= how many joules

1 joule = 1 kgm2s-2 Suppose mass = 100 kg, length = 1 km, time = 100 s Let say 1 joule = n1 * new unit(1 elouj) n1= 1 [kg/100 kg] [m2/106 m2][s/100s]-2 = 10-210-610-4 =10-12 joule 1 elouj = 10-12 joule

Suppose we employ a system in which the unit of mass equals 100 kg , the unit of length equals 1 km and the unit of time equals 100s
and call the energy eluoj (joule in reverse order) , then 1 elouj= how many joules

1 joule = 1 kgm²s^-2
Suppose mass = 100 kg, length = 1 km, time = 100 s
Let say 1 joule = n₁ * new unit(1 elouj)
n₁= 1 [kg/100 kg] [m²/10⁶ m²][s/100s]^-2
= 10^-210^-610^-4=10^-12joule
1 elouj = 10^-12joule