Question

team A has36 members and team B has48 members. if they are placed into tables of 6, how many more tables does team B need than team A?

Solve using split strategy a) 87*9 b)99*5 c)35*6

Answer 1

Answer :

1 ) Team A has 36 members and Team B has 48 members , and we placed them into table of 6 , So

Total number of table required to placed Team A = $\frac{36}{6}$ = 6 tables
And
Total number of table required to placed Team B = $\frac{48}{6}$ = 8 tables
So,
Team B required total tables more than Team A = 8 - 6 = 2 tables ( Ans )

2 ) Using split strategy , find value of

a ) 87 $\times$ 9

= ( 80 + 7 ) ​$\times$ 9

= 80 ​$\times$ 9 + 7 ​$\times$ 9

= 720 + 63

= 783 ( Ans )

b ) 99 $\times$ 5

= ( 90 + 9 ) ​$\times$ 5

= 90 ​$\times$ 5 + 9 ​$\times$ 5

= 450 + 45

= 495 ( Ans )​

c ) 35 $\times$ 6

= ( 30 + 5 ) ​$\times$ 6

= 30 ​$\times$ 6 + 5 ​$\times$ 6

= 180 + 30

= 210 ( Ans )​