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Question

ten calories of heat are added to two grams of liquid water.The temperature of the water (specific heat capacity of water is 1caloriegm degree C)

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Solution

Using the relation,
Energy = mass x specific heat x Change in temperature
10 cal = 2g x 1cal/g-ºC x dT
Change in temperature=10/2=5
Hence the temperature of water rises by 5 degree Celsius.

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