the amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510T.what is the amplitude of electric field part of the wave?

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Solution

Here,
B₀ = 510 T
E₀ = cB₀
c = 3×10⁸ m/s
E₀ = 3×10⁸×510
= 1.53 × 10¹¹ NC^-1

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the amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510T.what is the amplitude of electric field part of the wave?

Here, B0 = 510 T E0 = cB0 c = 3×108 m/s E0 = 3×108×510 = 1.53 × 1011 NC-1

Here,
B₀ = 510 T
E₀ = cB₀
c = 3×10⁸ m/s
E₀ = 3×10⁸×510
= 1.53 × 10¹¹ NC^-1