the electrical resistivity of silver is 1.60* 10 to the power -6 ohm meter .what wii be the resistance of a silver of length 10 m and cross sectional area 2 * 10 to the power -3.sq m?

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Solution

we now that
R = Ïl / A

where
A = 2 x 10^-3 m²
Ï = 1.6 x 10^-6 Î©.m
l = 10 m

so,
R = (1.6 x 10^-6 x 10 ) / 2 x 10^-3
or
R = (0.8 x 10^-5) / 10^-3

so, the resistance of the wire is
R = 8 x 10^-3 Î©

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the electrical resistivity of silver is 1.60* 10 to the power -6 ohm meter .what wii be the resistance of a silver of length 10 m and cross sectional area 2 * 10 to the power -3.sq m?

we now thatR = Ïl / A whereA = 2 x 10-3 m2 Ï = 1.6 x 10-6 Î©.ml = 10 m so,R = (1.6 x 10-6 x 10 ) / 2 x 10-3orR = (0.8 x 10-5) / 10-3 so, the resistance of the wire isR = 8 x 10-3 Î©

we now that
R = Ïl / A

where
A = 2 x 10^-3 m²
Ï = 1.6 x 10^-6 Î©.m
l = 10 m

so,
R = (1.6 x 10^-6 x 10 ) / 2 x 10^-3
or
R = (0.8 x 10^-5) / 10^-3

so, the resistance of the wire is
R = 8 x 10^-3 Î©