Question

The mass of CO₂ produced from 620 gm mixture of C₂H₄O₂ & O₂ , prepared to produce maximum energy is (Combustion reaction is exothermic)

(A) 413.33 gm

(B) 593.04 gm

(C) 440 gm

(D) 320 gm

Answer 1

1. The reaction is:

C₂H₄O₂ + 2 O₂ $\to$ 2 CO₂ + 2 H₂O

2. We see that 1 mole of ​ C₂H₄O₂​ produces 2 moles of CO₂
or
1 moleof CO₂ is produced by 0.5 mole of ​ C₂H₄O₂

3. Number of moles of ​ C₂H₄O₂ = $\frac{620}{60}=10.34moles$​
Number of moles of CO₂ = $\frac{10.34}{2}=5.17moles$

Mass of CO₂ = 5.17(44.01) = 227.38 g.