The motion of a body is given by the equation dv/dt=4-2v,where v is the speed in m/s and tin sec.If the body was at rest at t=0 then the magnitude of initial accelaration is :
1)3
2)4
3)5
4)10

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Solution

Given,
dv/dt=4-2 v(t)
According to question,
At t=0, v=0
or v(0)=0
For initial acceleration,
a=dv/dt=4-2 x v(0)
=4-0=4 m/s²

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The motion of a body is given by the equation dv/dt=4-2v,where v is the speed in m/s and tin sec.If the body was at rest at t=0 then the magnitude of initial accelaration is :1)32)43)54)10

Given, dv/dt=4-2 v(t) According to question, At t=0, v=0 or v(0)=0 For initial acceleration, a=dv/dt=4-2 x v(0) =4-0=4 ​m/s²

The motion of a body is given by the equation dv/dt=4-2v,where v is the speed in m/s and tin sec.If the body was at rest at t=0 then the magnitude of initial accelaration is :
1)3
2)4
3)5
4)10

Given,
dv/dt=4-2 v(t)
According to question,
At t=0, v=0
or v(0)=0
For initial acceleration,
a=dv/dt=4-2 x v(0)
=4-0=4 m/s²