Question

The population of a town increases by 10% every year. At pesent the population of the town is 363000. What was the population of the town years back

Answer 1

Suppose the population of the town a year back was x.
Percentage increase in population every year = 10%
So, present population of the town = $x+x\times \frac{10}{100}=363000$
$$\begin{gathered} \Rightarrow \frac{11x}{10}=363000 \\ \Rightarrow x=\frac{363000\times 10}{11}=330000 \end{gathered}$$
Therefore the population of the town a year back was 330000.