Question

the present age of a woman is 3 years more than three times the age of her daughter. three years hence, the woman's age will be 10 years more than twice the age of her daughter. find the present ages

Answer 1

let the present age of woman = x years

let the present age of daughter = y years

according to the given condition

x = 3y + 3

x - 3y = 3 ...............(1)

after 3 years :

woman's age =( x + 3 ) years

daughter's age = ( y + 3 ) years

according to the second condition

( x + 3 ) = 2 (y + 3) + 10

⇒ x - 2y = 13 .................(2)

subtracting (1) from (2) , we get

y = 10

put y = 10 in eq. (1) , we get

x = 33

so mother's present age = 33 years

daughter's present age = 10 years