The probabilities of a student getting grade A,B,C AND D are0.2,0.3,0.15,0.35 respectively. then the probability that a student gets at least C grade is
a)0.65 b)0.15 c)0.50 d)0.35

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Solution

P(A)=0.2; P(B)=0.3; P(C)=0.15; P(D)=0.35;

At least grade C means, the student can get either A, B or C.
So P(AUBUC)=P(A)+P(B)+P(C)=0.2+0.3+0.15=0.65.

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The probabilities of a student getting grade A,B,C AND D are0.2,0.3,0.15,0.35 respectively. then the probability that a student gets at least C grade isa)0.65 b)0.15 c)0.50 d)0.35

P(A)=0.2; P(B)=0.3; P(C)=0.15; P(D)=0.35; At least grade C means, the student can get either A, B or C. So P(AUBUC)=P(A)+P(B)+P(C)=0.2+0.3+0.15=0.65.

The probabilities of a student getting grade A,B,C AND D are0.2,0.3,0.15,0.35 respectively. then the probability that a student gets at least C grade is
a)0.65 b)0.15 c)0.50 d)0.35

P(A)=0.2; P(B)=0.3; P(C)=0.15; P(D)=0.35;

At least grade C means, the student can get either A, B or C.
So P(AUBUC)=P(A)+P(B)+P(C)=0.2+0.3+0.15=0.65.