Question

The rates of diffusion of CO2 and O3 were found to be 029 and 0271

respectively. Calculate the molecular mass of CO2, if the molecular mass of O3is 48.

Answer 1

We know that , rate of diffusion is inversely proportional to the square root of molecular mass so,
$$\begin{gathered} \frac{rat{e}_{c{o}_2}}{rat{e}_{o_3}}=\sqrt{\frac{M_{o_3}}{M_{c{o}_2}}} \\ Or,squaringbothsideweget, \\ \frac{0.{29}^2}{0.{271}^2}=\frac{48}{M_{c{o}_2}} \\ Or,M_{C{O}_2}=\frac{0.073441}{0.0841}x48=\frac{3525168}{84100}=41.9=42\left(nearly\right) \end{gathered}$$