The ratio by mass of carbon to oxygen in carbon
monoxide is(1) 3 : 8 (2) 8 : 3(3) 1 : 4 (4) 3 : 4

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Solution

Molar mass of carbon = 12 g mol-1
Molar mass of oxygen = 16 g mol^-1
Formula of carbon monoxide = CO
Ratio of carbon to oxygen in carbon monoxide is = $\frac{12}{16}$ = 3:4

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lim n \to \infty \frac{(1^{3} + 2^{3} + 3^{3} + . . . + n^{3}) (1^{4} + 2^{4} + 3^{4} + . . . + n^{4})}{(1^{8} + 2^{8} + 3^{8} + . . . + n^{8})}

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