The second order Bragg diffraction of X-rays with lambda = 1 Angstrom form a set of parallel planes in a metal occurs at an angle of 60 degrees. The distance between the scattering planes in the crystal is
1- 2 A 2- 1 A
3- 0.575A 4- 1.15 A

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Solution

Bragg's Law was given for the X-Ray difffraction.

nλ = 2d sinθ
n= order of diffraction
d = distance
Here, n=2 (second order)
λ = 1 A^o
θ = 60^o
So, put in the formula, 2 x 1 = 2 x d x $\frac{\sqrt{3}}{2}$
d= 1.154 A^o

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The second order Bragg diffraction of X-rays with lambda = 1 Angstrom form a set of parallel planes in a metal occurs at an angle of 60 degrees. The distance between the scattering planes in the crystal is1- 2 A 2- 1 A3- 0.575A 4- 1.15 A

Bragg's Law was given for the X-Ray difffraction. nλ = 2d sinθ n= order of diffraction d = distance Here, n=2 (second order) λ = 1 Ao θ = 60o So, put in the formula, 2 x 1 = 2 x d x 32 d= 1.154 ​Ao

The second order Bragg diffraction of X-rays with lambda = 1 Angstrom form a set of parallel planes in a metal occurs at an angle of 60 degrees. The distance between the scattering planes in the crystal is
1- 2 A 2- 1 A
3- 0.575A 4- 1.15 A

Bragg's Law was given for the X-Ray difffraction.

nλ = 2d sinθ
n= order of diffraction
d = distance
Here, n=2 (second order)
λ = 1 A^o
θ = 60^o
So, put in the formula, 2 x 1 = 2 x d x $\frac{\sqrt{3}}{2}$
d= 1.154 A^o