The semi perimeter of a triangle is 132 cm. The product of the difference of semi perimeter and it's respective sides is 13200 cubic cm. Find the area of the triangle.

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Solution

Answer :

1 ) Given semi perimeter s = 132 cm
And
( s - a ) ( s - b ) ( s - c ) = 13200 cm³

And we know area of heron's formula to find area

Area of triangle = $\sqrt{s (s - a) (s - b) (s - c)}$

So,

Area of triangle = $\sqrt{132 \times 13200}$

Area of triangle = $\sqrt{132 \times 132 \times 10 \times 10}$

Area of triangle = 1320 cm² ( Ans )

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The semi perimeter of a triangle is 132 cm. The product of the difference of semi perimeter and it's respective sides is 13200 cubic cm. Find the area of the triangle.

Answer : 1 ) Given semi perimeter s = 132 cm And ( s - a ) ( s - b ) ( s - c ) = 13200 cm3 And we know area of heron's formula to find area Area of triangle = s s - as - bs - c So, Area of triangle = 132 × 13200 Area of triangle = 132 × 132 × 10 × 10 Area of triangle = 1320 cm2 ( Ans )