Question

the velocity of freely falling body changes as g^pH^Pwhere g is a accelration due to gravity and h is the height the values p and q are

a.1, 0.5 b. 0.5 , 0.5 c. 0.5, 1 d. 1,1

Answer 1

For a freely falling body,
$v^2-u^2=2gH$
As the body is freely falling, u = 0
$$\begin{gathered} \Rightarrow v^2=2gH \\ \Rightarrow v=\sqrt{2gH} \end{gathered}$$
So, p = 0.5 and q = 0.5