Question

there is a hole in the bottom of tank having water. if total pressure at bottom is 3 atm (1atm= 10⁵N/m²); then the velocity of water flowing from the hole is :
a. root(400)m/s b. root(600) m/s.

Answer 1

$$\begin{gathered} velocityofthewaterisgivenby: \\ V=\sqrt{\frac{2P}{\rho }} \\ \rho isdensityofwater=1000kg/m^3 \\ V=\sqrt{\frac{2\times 3\times {10}^5}{1000}}=600m/s \end{gathered}$$