tina had a ribbon2/5m long.maya had a ribbon 3/5 m long.if both ribbons are joined what would be the length of 5 ribbons?

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Solution

Tina had a ribbon 2/5 m long.
Maya had a ribbon 3/5 m long.
When both ribbons are joined, then length of the ribbon = $\frac{2}{5} + \frac{3}{5} = \frac{5}{5} = 1 m$
So, length of 5 ribbons = $5 \times 1$ = 5 m

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tina had a ribbon2/5m long.maya had a ribbon 3/5 m long.if both ribbons are joined what would be the length of 5 ribbons?

Tina had a ribbon 2/5 m long. Maya had a ribbon 3/5 m long. When both ribbons are joined, then length of the ribbon = 25+35 = 55 = 1 m So, length of 5 ribbons = 5×1 = 5 m

Tina had a ribbon 2/5 m long.
Maya had a ribbon 3/5 m long.
When both ribbons are joined, then length of the ribbon = $\frac{2}{5} + \frac{3}{5} = \frac{5}{5} = 1 m$
So, length of 5 ribbons = $5 \times 1$ = 5 m