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Self Induction

transformer w...

Question

transformer works on the 220 v a.c mains to gave a supply of 8 v ,turn in primary coil is 4800 . find the turns in secondary coil

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Solution

$\frac{E_{o u t p u t v o l t a g e}}{E_{i n p u t v o l t a g e}} = \frac{N_{s e c o n d a r y}}{N_{p r i m a r y}} \frac{8}{220} = \frac{N_{s e c o n d a r y}}{4800} N_{s e c o n d a r y} = 174.5 = 175 N o o f t u r n s i n s e c o n d a r y c o i l i s 175 .$

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