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Question
Two balls are dropped to the gound from different heights. One ball is dropped 2 sec after he other, but both strike the ground at the same time 5s after the 1st is dropped.
a)What is the difference in the heights from which they were dropped?
b)From what height was the first ball dropped?
Two balls are dropped to the gound from different heights. One ball is dropped 2 sec after he other, but both strike the ground at the same time 5s after the 1st is dropped.
a)What is the difference in the heights from which they were dropped?
b)From what height was the first ball dropped?
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Solution
a)Let initially the first ball be at height h1, and takes t1 time to reach the ground = 5 second, and
let initially the second ball be at height h2, and takes t2 time to reach the ground = 5-2= 3second
for first Ball For second ball
s = ut+1/2gt2 s = ut+1/2gt2
h1 = 0 +1/2 g (5)2 h2 = 0 +1/2g(3)2
h1 = 25g/2 ...........1> h2 = 9g/2 .............2>
now the difference in height is h1 - h2 = 25g/2 - 9g/2
= 16g/2 =8g
8 x 9.8 =78.4 meter
b)first ball dropped from the height = h1 = 25g/2 =122.5 m
let initially the second ball be at height h2, and takes t2 time to reach the ground = 5-2= 3second
for first Ball For second ball
s = ut+1/2gt2 s = ut+1/2gt2
h1 = 0 +1/2 g (5)2 h2 = 0 +1/2g(3)2
h1 = 25g/2 ...........1> h2 = 9g/2 .............2>
now the difference in height is h1 - h2 = 25g/2 - 9g/2
= 16g/2 =8g
8 x 9.8 =78.4 meter
b)first ball dropped from the height = h1 = 25g/2 =122.5 m
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