Two balls of masses m and 2m are thrown vertically upward with same initial velocity. Maximum heights attained by them are h1 and h2 respectively. What is h1/h2 ?

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Solution

We can find the height using the third equation of motion.

v²-u²=2as

The height, s, will depend only on initial velocity, final velocity (0 in this case) and the acceleration due to gravity.It will not depend upon the mass.
here initial velocity of the two objects is also same.So They will rise to the same height.
So ratio of their heights i.e h1/h2 = 1

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